5. (4 points) A radio tuner consists of an RLC circuit with R = 0.800 2, & = 2.40 pH, and a variable capacitor. Suppose the capacitance is set so that the resonance frequency of the circuit is fo = 88.1 MHz. The radio antenna picks up a source that broadcasts at 102.1 MHz and provides a peak emf of 5.00 m V. What is the peak voltage across the inductor? Use this space for scrap work (will not be looked at or graded).Anyon Oberor 100 843215 This test is to be done individually and must represent your own work throughout. The first four ques- tions ary multiple choice, circle the best option. Your work for the multiple choice questions will not be graded. The last question b a long problem; show all your work for full marks on the provided problem solving worksheet Keep this hot stapled together. I. (1 point] Which of the following is true for the magnitude of the instantaneous value of the end phasor A The magnitude is decreasing LOOV B. The magnitude is increasing. C The magnitude is constant D. You can't know anything from the dia- -LOO V 2. (1 point) A low-pass filter consists of a 127 ( resistor and a 0,000163 F capacitor in series with each other. The AC source has a peak voltage of 7.90 V. What is Ve if the frequency is 700 Ha A. 5.32 V B. 754 V 253( 7) (0 000163 ) C 414V Ve = VO . He 139.48 7 =(740V) . (139.4872 HEY12 = 5. 84 6 3. (1 point) If a low-pass RC filter has a cross over frequency f. - 650. Fix, what will the crossover fre- queney be if the capacitance & is doubled? = 650 A 460 H 253 RL B, 650 Ha C. 1300 Hz = = (650 ) = 325 +2 D 325 He 2 33RC 4. (1 point) In a motor for a drill the current lags the voltage by 32.0". The motor draws an rms current of 4.90 A at a voltage of 160. V rms. What is the motor's power? 4 665 W B. 784 W C. 8.36 x 10' W P = Jims . Vims cost D. 415 W = 4,90 . 160 (05 3 2 = 6 64. 26 W