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5. A 0.114-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points x1 = -0.263 m and x2 = 0.445 m.
5. A 0.114-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points x1 = -0.263 m and x2 = 0.445 m. The period of oscillation is 0.637 s. Find the frequency (f), the equilibrium position (xeq), the amplitude (A), the maximum speed (Umax), the maximum magnitude of acceleration (amax), the force constant (k), and the total mechanical energy (Etot).
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Given Mass m 0114 kg Period T 0637 s x 1 0263 m x 2 0445 m To calculate the various quantities relat...
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Physics for Scientists and Engineers A Strategic Approach with Modern Physics
Authors: Randall D. Knight
4th edition
978-0134092508, 134092503, 133942651, 978-0133942651
