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5. Compute the torque T, and Tc due to tensile forces in the belts at point B and C, respectively. 6. Draw the torque
5. Compute the torque T, and Tc due to tensile forces in the belts at point B and C, respectively. 6. Draw the torque diagram to show the level of torque in all segments of the shaft. 7. Compute the nominal torsional stress and Ta on the outer surface of the shaft for cross sections passing through points B and C due to the torque T and Tc 8. What is the value of the shear stress at the center of the cross section passing through point B and that passing through point C? 9. Assuming that the shaft is made of steel, compute the angle of twist of the cross section passing through B with respect to that passing through point C. 10. Determine the stress concentration factor K, in torsion, for a sled-runner keyseat 11. Using the stress concentration factor K, just determined, calculate the shear stresses T and on the outer surface of the shaft for cross sections passing through points B and C, respectively. Key Design 12. Determine the force F that the shaft exerts on the key. 13. Suggest the dimensions (length, width, and height) of the key if it was made of steel. (there are many possible solutions). E:=207 GPa R:= L: 600 mm D: 28 mm D 2 v: 0.292 = 0.014 m nom:= P A Yb= Yc= Torque on pully b and c 0.12 T (1400-400) 2 Nominal Torsional Tb. R 32 20137.972 kPa 0.24 T: (610-110).. = 60 2 K:= 1.6 32 (28) T.R 1 P: 6.2 kN A:=- 2 (28) P.L A.E =60 8:= = (5.837.10-5) m = Ey=v .D 4 Stress due to compressive force is =Knom= (3.222.10) kPa = (1.392.10). m = (3.079.10-) m nom = (1.392.10-5) m da: D.Ey=-7.954.10-7 m -=-2.841.10-5 P = 6.2 KN Bearing 200 mm 120 mm-dia. pulley B 200 mm 28 mm-dia. 400 N 1400 N 200 mm 610 N 110 N t 240 mm-dia. pulley D Thrust Bearing P = 6.2 kN
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