Question
5) Confidence Interval problem for two population DIFFERENCES (not means or proportions) that have the SAME NUMBER OF DATA VALUES (n1 = n2). Using the
5) Confidence Interval problem for two population DIFFERENCES (not means or proportions) that have the SAME NUMBER OF DATA VALUES (n1 = n2). Using the same traffic count data and statistics as above, the margin of error, E, formula is E = t-critical * sd/sqrt(n) We will assume a significance level of = 5%(95% confidence level) with n=10 data points, hence df = (10 - 1 ) = 9, so t-critical =______ ? What are the MEAN ______and SD _____for the "differences"?
E = _______ * _______ / ______ = __________ (fill in the different values and the calculated result) .
Our Confidence Intervalis (d-bar - E) <d < (d-bar + E) = _________ <d < __________
Real-world Conclusion: Whose median income mean is larger and by how much?
(IF this or any CI includes zero there is NO difference)
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