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5. Consider the balanced equation below in which 10.86 grams of PCl5 reacts with 13.58 grams of AsF3.3(30.94)+s(3s.45)=270.16 3PCl5+5AsF33PF5+5AsCl3s(74.92)+3(18.90)=431.54 What is the excess reactant? A.
5. Consider the balanced equation below in which 10.86 grams of PCl5 reacts with 13.58 grams of AsF3.3(30.94)+s(3s.45)=270.16 3PCl5+5AsF33PF5+5AsCl3s(74.92)+3(18.90)=431.54 What is the excess reactant? A. PCCl5 B. AsF3 How many grams of excess reactant are left over after the reaction is complete? grams
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