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5: Details of dict_by_drug: The dict_by_drug function takes a dict argument in the form of the data structure above. (a dict whose keys are dates

5: Details of dict_by_drug: The dict_by_drug function takes a dict argument in the form of the data structure above. (a dict whose keys are dates (str), each associated with an inner dict whose keys are drug names (str) and whose associated value is a tuple of int transactions) and returns a dictionary (dict or defaultdict) associating a drug name (str) with another dictionary: this inner dictionary associates a date (str) with a tuple of int representing all its transactions (non-0 int values). So calling this function with the db1 dictionary shown above dict_by_drug( db1 ) returns a dictionary whose contents are {'Azor': {'2016-04-01': (100, -3, -3, 1), '2016-04-02': (-3, -3, 2)), 'Benz': {'2016-04-01': (4, 2, -3)}, 'Depr': {'2016-04-02': (4, -7)}, 'Caml': {'2016-04-02': (6, -2, -3)}} Of course, dictionaries print on one line, and can print their key/values (value) in any order, because they are not ordered.

def dict_by_drug(db : {str:{str:(int,)}}) -> {str:{str,(int)}}:

if name == 'main':

if prompt.for_bool('Test dict_by_drug?', True): db1 = {'2016-04-01': {'Benz': (4, 2, -3), 'Azor': (100, -3, -3, 1)}, '2016-04-02': {'Depr': (4, -7), 'Azor': (-3, -3, 2), 'Caml': (6, -2, -3)}} print(' argument =',db1) answer = dict_by_drug(db1) print(' answer =', answer) check(answer, {'Caml': {'2016-04-02': (6, -2, -3)}, 'Depr': {'2016-04-02': (4, -7)}, 'Azor': {'2016-04-01': (100, -3, -3, 1), '2016-04-02': (-3, -3, 2)}, 'Benz': {'2016-04-01': (4, 2, -3)}})

db1 = {'2016-04-02': {'Azor': (-5, -2, 3, -1, -7), 'Efos': (-3, 20, -7), 'Caml': (4, 6, -2, 20, -8, -3)}, '2016-04-03': {'Benz': (-4, 16), 'Azor': (-4,), 'Efos': (4, 1, 30), 'Caml': (-2, -2, -3, -2)}, '2016-04-01': {'Benz': (4, 2, -3, 20), 'Depr': (30, -2, -5, -10, -2), 'Azor': (20, -3, -3, 1), 'Efos': (4, -7), 'Caml': (4, 6, -2, 1, -8, -3)}} print(' argument =',db1) answer = dict_by_drug(db1) print(' answer =', answer) check(answer, {'Caml': {'2016-04-03': (-2, -2, -3, -2), '2016-04-01': (4, 6, -2, 1, -8, -3), '2016-04-02': (4, 6, -2, 20, -8, -3)}, 'Azor': {'2016-04-02': (-5, -2, 3, -1, -7), '2016-04-01': (20, -3, -3, 1), '2016-04-03': (-4,)}, 'Benz': {'2016-04-01': (4, 2, -3, 20), '2016-04-03': (-4, 16)}, 'Efos': {'2016-04-03': (4, 1, 30), '2016-04-01': (4, -7), '2016-04-02': (-3, 20, -7)}, 'Depr': {'2016-04-01': (30, -2, -5, -10, -2)}})

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