5. Ho: p=0.73 Ha: p20.73 n=100 p=0.59 Test statistic: J. 153 p-value: 0, 00 1 6 - 2 Are the results of this study unusual? Explain. since the p-value is close to commonly used signific ance level s, and the test Statistic is in the interval ( - 3. 5 , 3 15 ) ,we fail to notice any unusual results in this test. 6. Calculate the p-value for the scenario in problem 4 if it was changed to a two-tailed test. p-value:_ 7. Calculate the p-value for the scenario in problem 5 if it was changed into a left-tailed test. p-value: 0. 00of StatswithHogan02018