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nu\". - aw mg Lu\" - math 27 ' Final Exam A researcher wishes to estimate the percentage of adults who support abolishing the penny. What size sample should be obtained if he wishes the estimate to bewithm 5 . v . , . 99% condence if (a) he uses a previous estimate of 26%? (b) he does not use any prior estimates? gig here to view the standard normal distn'bution table (page 1); Stick hem to view the standard normal distribution table (me 2)_. ' (Round up to the nearest integer.) l (Round up to t'he nearest integer.) 8:33 Submit Test { 6 of 28 (4 complete) V b R Suppose a life insurance company sells a $180,000 1-year term life insurance policy to a 20-year-old female for $170. According to the National Vital Statistics Report, 58(21), the probability that the female survtves the year is 0.999544. Compute and interpret the expected value of this policy to the insurance company. The expected value is $ (Round to the nearest cent as needed.) Which of the following interpretations of the expected value is correct? Select the correct choice below and ll in the answer box to complete your choice. (Round to the nearest cent as needed.) 0 A. The insurance company expects to make a maximum profit of $ on every 20-year-old female it insures for 1 year. 0 3_ The insurance company expects to make a prot of $ on every 20-year-old female it insures for 1 month. 0 C. The insurance company expects to make a minimum prot of $ on every 20-year-old female it insures for1 month. 0 D. The insurance company expects to make a prot of $ on every 20year-old female it insures for 1 year. Click to select your answer(s). \fThis Question: 5 pts 8 of 28 (9 complete) This Test: 60 p According to the manufacturer of M&Ms, 13% of the plain M&Ms in a bag should be brown, 14% yellow, 13% red, 24% blue, 20% orange, and 16% green. A student randomly selected M&Ms. He counted the number of M&Ms of each color and obtained the results shown in the table. Test whether plain M&Ms follow the distribution stated by the manufacturer at the a = significance. Click the icon to view the table. Red 55 Blue 62 Orange 93 Green 67 What is the test statistic? XO = (Round to three decimal places as needed.) What is the P-value of the test? P-value = (Round to three decimal places as needed.) Based on the results, do the colors follow the same distribution as stated in the problem? Ho. There is evidence that the distribution of colors is stated by the manufacturer. Click to select your answer(s). MacBook Pro DO 006 FB esc F1 F3 F4 O 5\" Final Exam 190mins complete) v 1 } Acredit score is used by credit agencies (such as mortgage companies and banks) to assess the creditworthiness of individuals. Values range from 300 to 850. with a credit more over TOD considered to be a quality credit risk. According to a survey. the mean credit score is 704.2. A credit analyst wondered whether high-income individuals (incomes in excess of 5100.000 per year} higher credit scores. He obtained a random sample of 41 high-income individuals and found the sample mean credit score to be 717.8 with a standard deviation of 82.3. Conducttho amp!\" to determine if highincome individuals have higher credit scores at the or: 0.05 level of signicance. State the null and alternative hypotheses. als. 06 not round.) to = V 1(Round to two decimal places as needed.) Identify the P-value. P-value = V . W . . V L (Round to three decimal places as needed.) Make a conclusion regarding the hypothesis. E the null hypothesis. There [3 sufficient evidence to claim that the mean credit score of highincome individuals is 3 Enter your answer in each of the answer boxes. Test: Final Exam Time Remaining: 02:44:53 Submit Test This Question: 2 pts 10 of 28 (9 complete) This Test: 60 pts possible A headline read, "More Than Half of Americans Say Federal Taxes Too High." The headline was based on a random sample of 1094 adult Americans in which 568 stated the amount of federal tax they have to pay is too high. Is this an accurate headline? Assume the a = 0.01 level of significance Identify the null and alternative hypotheses for this test. O A. Ho: P = 0.50 O B. Ho: p # 0.50 O C. Ho: p = 0.50 Hy: p # 0.50 H1 : p = 0.50 Hy : p > 0.50 O D. Ho: p > 0.50 O E. Ho: p = 0.50 OF. Ho: p _i12 03- H()1l11=l12-H13l11P2 09- H01P1>P21H11P1