5) Using the IP address and subnet mask shown write out the host address: Host Address IP Address and Subnet Mask 192.149.24.191 255.255.255.0 117.15.2.51 255.0.0.0 27.125.200.151 255.0.0.0 223.169.23.20 255.255.0.0 48.21.25.54 255.255.0.0 199.120.150.35 255.255.255.0 10.10.10.10 255.0.0.0 191.55.165.135 255.255.255.0 10.10.48.80 255.255.255.0 188.10.18.2 255.255.0.0 6) Write the correct default subnet mask for each of the following addresses: IP Address 126.123.23.1 223.69.230.250 192.12.35.105 Subnet Masks (10 Marks) (10 Marks) IP Address 77.251.200.51 189.210.50.1 88.45.65.35 128.212.250.254 193.100.77.83 125.125.250.1 1.1.10.50 Subnet Masks 7) Given the address 23.56.7.91 and the default class A mask, find the beginning address (network address). (2 Marks) 8) Given the address 132.6.17.85 and the default class B mask, find the beginning address (network address). (2 Marks) 9) Consider the IP address of 182.133.129.55. a) What is the class of this network if classful addressing was used? b) How many bit long is the network-ID if classful addressing was used? c) What is the network ID and host-ID of our computer? d) What is the default network mask? e) How many network hosts (computers) can be addressed in this network? (6 Marks)