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5.1 (10 points) Let f:{0,1}{0,1} be an efficiently computable injective (i.e., one to one) function. Show that if f has a hard-core predicate as in
5.1 (10 points) Let f:{0,1}{0,1} be an efficiently computable injective (i.e., one to one) function. Show that if f has a hard-core predicate as in Definition7 then f is one way. 5.2 (10 points) Is this implication necessarily true when G not injective? Either prove or show a counter example
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