Question
54 27 21 6 7 39 5 3 49 6 7 37 46 46 38 27 47 43 52 31 52 57 22 29 47
54 | 27 | 21 | 6 | 7 |
39 | 5 | 3 | 49 | 6 |
7 | 37 | 46 | 46 | 38 |
27 | 47 | 43 | 52 | 31 |
52 | 57 | 22 | 29 | 47 |
10 | 19 | 13 | 37 | 12 |
11 | 4 | 13 | 29 | 8 |
54 | 26 | 31 | 35 | 10 |
19 | 22 | 4 | 12 | 6 |
6 | 49 | 59 | 12 | 11 |
- Use the table above to create an 80%, 95%, and 99% confidence interval.
- Choose another confidence level (besides 80%, 95% or 99%) to create another confidence interval.
Sample Size n = 50
Sample Mean = x = X/n = 26.2000
Sample Standard Deviation = s = ((X- x )/(n-1) ) = 17.68777
80%
Level of Significance , = 0.2
degree of freedom= DF=n-1= 49
't value=' t/2= 1.299 [Excel formula =t.inv(/2,df) ]
Standard Error , SE = s/n = 17.6878/50= 2.5014
margin of error , E=t*SE = 1.299*2.5014= 3.24953
Confidence interval is
Interval Lower Limit = x - E = 26.2-3.2495= 22.95047
Interval Upper Limit = x + E = 26.2+3.2495= 29.44953
80% Confidence interval is (22.95 < < 29.45 )
95%
Level of Significance , = 0.05
degree of freedom= DF=n-1= 49
't value=' t/2= 2.010 [Excel formula =t.inv(/2,df) ]
Standard Error , SE = s/n = 17.6878/50= 2.5014
margin of error , E=t*SE = 2.01*2.5014= 5.02681
Confidence interval is
Interval Lower Limit = x - E = 26.2-5.0268= 21.17319
Interval Upper Limit = x + E = 26.2+5.0268= 31.22681
95% Confidence interval is 21.17 < < 31.23 )
99%
Level of Significance , = 0.01
degree of freedom= DF=n-1= 49
't value=' t/2= 2.680 [Excel formula =t.inv(/2,df) ]
Standard Error , SE = s/n = 17.6878/50= 2.5014
margin of error , E=t*SE = 2.68*2.5014= 6.70371
Confidence interval is
Interval Lower Limit = x - E = 26.2-6.7037= 19.49629
Interval Upper Limit = x + E = 26.2+6.7037= 32.90371
99% Confidence interval is 19.50 < < 32.90 )
- Provide a sentence for each confidence interval created above which explains what the confidence interval means in context of topic of your project.
80% Confidence interval is (22.95 < < 29.45 )
This implies that we are 80% confident that the mean lies between 22.95 and 29.45 with a margin error of 3.24953 .
95% Confidence interval is 21.17 < < 31.23 )
This means that we are 95% confident that the mean scores lies between 21.17 and 31.23 with a margin error of 5.02681
99% Confidence interval is 19.50 < < 32.90 )
This means that we are 99% confident that the mean scores lies between 19.50 and 32.90 with a margin error of6.70371
--------------------------------------------------------QUESTION-----------------------------------------------------
(Round the mean and sample standard deviation to values to FIVE decimal places)
Sample Mean =
Sample Standard Deviation =
(Round the lower/upper limits and margin of error to THREE decimal places).
80% Confidence Interval:
80% Confidence Interval Margin of Error:
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