6. [1.0 point] Consider the situation shown below, where a uniform meter stick of mass M is used as a seesaw and its center of mass (CM) is n_ot located over the fulcrum. For the meter stick to be balanced [that is, to be in static equilibrium) by the placement of two masses, m1 and m2, there must be zero net torque. Write an equation that species the net torque applied to the meter stick by the weight of mass ml, the weight of mass m2, and the weight of the meter stick, relative to the axis of rotation that is at the fulcrum, in terms of the quantities shown in the drawing. [Remember that mass is not identical to weight.) X1 X2 m -:XCME4 m l ' ' [I 2 M CM Fulcrum Solve the equation you wrote for the net torque to obtain the following expression for the mass of the meter stick: mxmx (4) M: 11 22 xcm Show your work