$67$ The ${?}^{238}U$ nucleus has a binding energy of about $7\mathrm{.}6$ MeV per nucleon. If the nucleus were to fission into two equal fragments, each would have a kinetic energy of just over $100$ MeV $.$ From this, it can be concluded that

$($A$){?}^{238}U$ cannot fission spontaneously

$($B$){?}^{238}U$ has a large neutron excess

$($C$)$ nuclei near $A=120$ have masses greater than half that of ${?}^{238}U$

$($D$)$ nuclei near $A=120$ must be bound by about $6\mathrm{.}7$ MeV$/$nucleon

$($E$)$ nuclei near $A=120$ must be bound by about $8\mathrm{.}5$ MeV$/$nucleon