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6. A consumer analyst would like to estimate the proportion of adults who shop for groceries on a weekly basis. A random sample of 728
6. A consumer analyst would like to estimate the proportion of adults who shop for groceries on a weekly basis. A random sample of 728 adults is surveyed, and the sample proportion who shop for groceries on a weekly basis is found to be approximately 0.65. If the analyst wants to use this information to construct a 95% confidence interval, what will the margin of error be? As you compute the margin of error, try not to do a lot of rounding until you reach the end of your calculations, and then choose the answer below that is closest to what you calculate. A. 1.960 B. 0.018 C. 0.027 D. 0.035 E. 0.050
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