(6) Find an equation [01" the tangent plane to the graph of z = f (:1:1 :9!) at the point (2,2,0), where 3 = f(3:, y) is; implicitly defined by 1'3; + 1-2 + yz 111(::2 + 1) = ,1_ Hint: write this Surface as a lime] surfam of the form: F(J:,y,:] = constant. Then compute the gradient of F