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6 Firefox File Edit View History Bookmarks Tools Window Help @ 7,5 C1 E '6? 627.9} Mon 5:34 PM Q o BE r ' O
6 Firefox File Edit View History Bookmarks Tools Window Help @ 7,5 C1 E '6? 627.9} Mon 5:34 PM Q o BE r ' O O O ' "ix Midterm Exam-MAT135,sec\\i x + V 6 7 C 0 E] https://www'webassign.net/web/Student/AssignmeniResponses/submit?dep=3'l640076&tags=autosave#queson1923673_'l6 E 3:} a E 17. [9/13 Points] I DETAILS PREVIOUS ANSWERS I AUFCAT7 3.1.041.MI.SA. MY NOTES I I ASK YOUR TEACHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Use synthetic division and the Factor Theorem to determine whether the given binomial is a factor of F(x). P(x) = x5 + 5X4 27x3 51xZ + 60x, x 4 Part1of5 Begin with performing synthetic division with c = 4 /) 4 and examine the remainder. 4 1 s 27 51 60 o 4 36 IV ,2 36 60 E y 720 1 9y ,)9 9y /)9 15 0;; 720 DJ ,)0 PaZofS Based on the synthetic division from the step above, the remainder is 0 y / 0 . Therefore, P(4) = 0 v 7/) 0 Now recall the Factor Theorem. A polynomial P(x) has a factor (x c) if and only if P(c Submit g (you cannot come back) 3 6 Firefox File Edit View History Bookmarks Tools Window Help @ 7,. C1 E '3\" 627.9} Mon5:34PM q o s-_- , e * O O I Wx MidtermExam-MAT135,sec\\i x + V ' 4' C 0 E] https://wwwiwebassign.net/web/Student/AssignmentResponseslsubmit?dep=3'l640076&tags=autosave#queson1923673_'l6 E i} i] E 17. [9/13 Points] I DETAILS PREVIOUS ANSWERS I AUFCAT7 3.1.041.MI.SA. MY NOTES I I ASK YOUR TEACHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Use synthetic division and the Factor Theorem to determine whether the given binomial is a factor of F(x). P(x) = x5 4- 5X4 27x3 51xZ + 60x, X 4 Part1of5 Begin with performing synthetic division with c = 4 J /) 4 and examine the remainder. 4 1 s 27 51 60 o 4 36 IV ,236 60 3.; /20 1 9J ,)9 9" /)9 15 0.; 720 y /0 PaZofS Based on the synthetic division from the step above, the remainder is 0 y /} 0 . Therefore, P(4) = 0 j.) 0 Now recall the Factor Theorem. A polynomial P(x) has a factor (x c) if and only if P(c) 0. That is, (X c) is a factor of P(x) if and only if . Submit g (you cannot come back)
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