6 mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=620257974&question|d=1&flushed=fa|se&cld=6873279¢erwin=yes E Math 159-14 Spring 2022 JOU HAN HUANG 03/11/2212:47 PM Question 11, 6.2.25 ) HW Score: 1.25%, 0.25 of 20 points : Homework: Chapter6 Homework parts,\" 9 Points: 0.25 of1 A survey found that women's heights are normally distributed with mean 63.5 in and standard deviation 2,5 in. A branch of the military requires women's heights to be between 58 in and 80 in. 3. Find the percentage of women meeting the height requirement. Are many women being denied the opportunity to join this branch of the military because they are too short or too tall? b. If this branch of the military changes the height requirements so that all women are eligible except the shortest 1% and the tallest 2%, what are the new height requirements? Click to view page 1 of the table. Click to view page 2 of the table. a. The percentage of women who meet the height requirement is 98.61'%, (Round to two decimal places as needed.) Are many women being denied the opportunity to join this branch of the military because they are too short or too tall? A. Yes, because the percentage of women who meet the height requirement is fairly large. N B. No, because only a small percentage of women are not allowed to join this branch of the military because of their height. C. No, because the percentage of women who meet the height requirement is fairly small. D. Yes, because a large percentage of women are not allowed tojoin this branch of the military because of their height. h. For the new height requirements, this branch of the milimry requires women's heights to be at least 57.7V in and at most 68.6' in. (Round to one decimal place as needed.) Help me solve this Wow an example Get more help ' S rlar question 6 mylab.pearson.com/Student/PlayerHomeworktaspx?homeworkld=620257974&question|d=1&f|ushed=false&cld=6873279¢erwin=yes E Math 159-14 Spring 2022 JOU HAN HUANG 03/11/2212248 PM Question 12, 6.2.27-T ) HW Score: 125%, 0125 of 20 points : Homework: Chapter6 Homework parts\" [>0 Points: 0 of1 A survey found that women's heights are normally distributed with mean 625 in and standard deviation 31 in. The survey also found that men's heights are normally distributed with mean 69.7 in. and standard deviation 3.9 in. Most of the live characters employed at an amusement park have height requirements of a mInImum of 56 in. and a maximum of 63 in Complete parts (a) and (b) belowt a. Find the percentage of men meeting the height requirement. What does the result suggest about the genders of the people who are employed as characters at the amusement park? The percentage of men who meet the height requirement is 4.27'%. (Round to two decimal places as needed.) Since most men do not mes? the height requirement, it is likely that most of the characters are women.' b. If the height requirements are changed to exclude only the tallest 50% of men and the shortest 5% of men, what are the new height requirements? The new height requirements are a minimum of 63.3' in. and a maximum of 69.1' in. (Round to one decimal place as needed.) Help me solve this Wew an example Get more help - S Ilar question 6 mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=620257974&question|d=1&f|ushed=false&cld=6873279¢erwin=yes E Math 159-14 Spring 2022 JOU HAN HUANG O3/11/2212:49 PM Question 13, 6.3.9-T ) HW Score: 1.92%, 0.38 of 20 points : Homework: Chapter 6 Homework pan ,4 0,4 9 Points: 0.13 of 1 Three randomly selected children are surveyed. The ages of the children are 4, 5, and 9. Assume that samples of size n = 2 are randomly selected with replacement from the population of 4, 5, and 9. Listed below are the nine different samples. Complete parts (a) through (d) 4,4 4,5 4,9 5,4 5,5 5,9 9,4 9,5 9,9 Q1 a. Find the value of the population median. 5 (Type an integer or a decimal. Do not round.) b. Find the median of each of the nine samples, then summarize the sampling distribution of the medians in the format of a table representing the probability distribution of the distinct median values. Sample Median Probability V 1 4 _ 9 * 4 5 2 9 * 5 1 9 * V 2 6.5 9 * V 2 7 _ 9 * V 1 9 a (Type integers or simplied fractions.) 0. Find the mean of the sampling distribution of the sample median. 6' (Type an integer or a decimal. Do not round.) d. Based on the preceding results, is the sample median an unbiased estimator of the population median? Why or why not? A. The sample median does not target the population median. As such, the sample median makes a good estimator of the population median. .X n TL. NW...\" \"may... um.-." um -nmnnm... \"mum. A, \"my. m- MM- \"Nu... mm,\" .. \"NV; Nah\"... nun..- \"mum\"... \"Nu". Help me solve this Wew an example Get more help - S Ilar question mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=620257974&questionld=1&flushed=false&cld=6873279¢erwin=yes GZ Math 159-14 Spring 2022 JOU HAN HUANG 03/11/22 12:49 PM Homework: Chapter 6 Homework Question 13, 6.3.9-T HW Score: 1.92%, 0.38 of 20 points Part 4 of 4 Points: 0.13 of 1 Save Three randomly selected children are surveyed. The ages of the children are 4, 5, and 9. Assume that samples of size n = 2 are randomly selected with replacement from the population of 4, 5, and 9. Listed below are the nine different samples. Complete parts (a) through (d). 4,4 4,5 4,9 5,4 5,5 5,9 9,4 9,5 9,9 . Find the median of each of the nine samples, then summarize the sampling distribution of the medians in the formal of a table represenung the probability distribution of the disunct median values. Sample Median Probability 4.5 5 601 - 60 / N 6/N 61 - 6 / N 61 - 6.5 7 9 (Type integers or simplified fractions.) c. Find the mean of the sampling distribution of the sample median. 6 (Type an integer or a decimal. Do not round.) d. Based on the preceding results, is the sample median an unbiased estimator of the population median? Why or why not? A. The sample median does not target the population median. As such, the sample median makes a good estimator of the population median. B. The sample median targets the population median. As such, the sample median makes a good estimator of the population median. C. The sample median does not target the population median. As such, the sample median does not make a good estimator of the population median. D. The sample median targets the population median. As such, the sample median does not make a good estimator of the population median. Help me solve this View an example Get more help - Similar question6 mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=620257974&question|d=1&f|ushed=fa|se&cld=6873279¢erwin=yes E Math 159-14 Spring 2022 JOU HAN HUANG O3/11/2212:50 PM Question 14, 6.3.10-T > HW Score: 2.47%, 0.49 of 20 points : Homework: Chapter 6 Homework Farm.\" 9 points: 0.11 on Three randomly selected children are surveyed. The ages of the children are 2, 6, and 7. Assume that samples of size n = 2 are randomly selected with replacement from the population of 2, 6, and 7. Listed below are the nine different samples. Complete parts (a) through (d). 2,2 2,6 2.7 6.2 6,6 6,7 7,2 7,6 7,7 Q1 a. For the population. nd the proportion of odd numbers. The proportion is 0.333'. (Round to three decimal places as needed.) h. Find the proportion of odd numbers of each of the nine samples, then summarize the sampling distribution of the medians in the format of a table representing the probability distribution of the distinct proportion values. Sample Proportlon Probability 0 4' 9 V_ ' 4 0.5 9 calx (Type integers or simplied fractions.) c. Find the mean of the sampling distribution of the sample proportion of odd numbers. The mean is 0.333'. (Round to three decimal plaoes as needed.) d. Based on the preceding resulb, is the sample proportion an unbiased estimator of the population proportion? Why or why not? 'x A. The sample proportions target the proportion of odd numbers in the population, so sample proportions do not make good estimators of the population proportion. B. The sample proportions do not target the proportion of odd numbers in the population, so sample proportions do not make good estimators of the population proportion. C. The sample proportions do not target the proportion of odd numbers in the population, so sample proportions make good estimators of the population proportion. * D. The sample proportions target the proportion of odd numbers in the population, so sample proportions make good estimators of the population proportion. Help me solve this View an example Get more help . S lar question 6 mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=620257974&question|d=1&f|ushed=false&cld=6873279¢erwin=yes E Math 159-14 Spring 2022 JOU HAN HUANG O3/11/2212:51 PM Question 15I 6.3.11 HW Score: 3.1 %, 0.62 of 20 points : Homework: Chapter6 Homework @ Points: 0.13 of, The assets (in billions of dollars) of the four wealthiest people in a particular country are 46, 25, 15, 12. Assume that samples of size n = 2 are randomly selected with replacement from this population of four values. a. After identifying the 16 ditTerent possible samples and nding the mean of each sample, oonstruct a table representing the sampling distribution of the sample mean. In the table, values of the sample mean that are the same have been combined. x Probability x Probability 46 1 V 20 2 V 16 16 V V 35 5 2 18 5 2 ' 16 ~ 16 V V 30 5 2 15 1 ' 16 16 29 2 V 13 5 2 V 16 ~ 16 V V 25 1 12 1 16 16 (Type integers or fractions.) It. Compare the mean of the population to the mean of the sampling distribution of the sample mean. The mean of the population, 24.50', is equal to ' the mean of the sample means, 2450'. (Round to two decimal places as needed.) c. Do the sample means target the value of the population mean? In general, do sample means make good estimates of population means? Why or why not? The sample means target ' the population mean. In general, sample means do make good estimates of population means because the mean is an unbiased estimator. Help me solve this View an example Get more help . S lar