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(6%) Problem 11: Pablo and Jacob are running a half marathon. Jacob is d = 49.5 m behind Pablo, and both are running at the

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(6%) Problem 11: Pablo and Jacob are running a half marathon. Jacob is d = 49.5 m behind Pablo, and both are running at the same speed, vo = 2.83 m/s. At a particular moment, Jacob begins to accelerate forward at a constant rate of a = 0.044 m/s. @theexpertta.com - tracking id: 5188-75-0E-46-BB99-46077. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. A 17% Part (a) Using the variables from the problem statement, write an expression for the time it takes Jacob to catch Pablo. Grade Summary t = 01 Deductions 0% Potential 100% Y 7 8 9 HOME Submissions a TA 4 5 6 Attempts remaining: 12 (5% per attempt) h 1 2 3 detailed view k m n1 END P VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback. A 17% Part (b) Using the variables from the problem statement, write an expression for the distance Jacob traveled as he was accelerating to catch Pablo. A 17% Part (c) Using the variables from the problem statement, write an expression for Jacob's speed at the time he catches up to Pablo. A 17% Part (d) What is the time, in seconds, it takes Jacob to catch Pablo? A 17% Part (e) What is the distance, in meters, Jacob traveled as he was accelerating to catch Pablo? A 17% Part (f) What is Jacob's speed, in meters per second, at the instant he catches up to Pablo?(6%) Problem 12: A police car waits in hiding slightly off the highway. A speeding car is spotted by the police car traveling at speed s = 37.8 m/s. At the instant the speeding car passes the police car, the police car accelerates forward from rest at a constant rate of a = 3.5 m's to catch the speeding car. Assume the speeding car maintains its speed. @theexpertta.com - tracking id: 5T88-75-0E-46-BB99-46077. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. 4 50% Part (a) Write an expression for the time it takes for the police car to catch the speeding car. Use the variables from the problem statement for your expression. Grade Summary Deductions 0% Potential 100% 7 8 9 HOME Submissions 4 5 6 Attempts remaining: 12 (5% per attempt) J 1 2 3 detailed view END BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback. 4 50% Part (b) How long, in seconds, does it take for the police car to catch the speeding car?(6%} Problem 9: An unwary football player collides headon with a padded goalpost while running at . .9 m.-'s and comes to a full stop after compressing the padding and his bodv by 9.35 111. Take the direction of the player's initial \\'elocit3r as positive. $3 50% Part (:1) Assuming constant acceleration= calculate his acceleration during the collision= in meters per second squared. a: Degrees '32} Radians Submit Hint Feedback I give up! Hlints: deduction per hint. Hints remaining: _ Feedback: deduction per feedback. Grade Sum ma r_\\' Deductions Potential 95% Submissions Attempts remaining: t per attempt) detailed View 1 Q, 50% Part (13) How long does the collision last in seconds? J" mum-.9 :2: 1r1: Drum TA 1 i r' 6%) Problem 4: A particle moves along the x axis and its position as a function of time is x(t) = (18.2 m/s)t - (1.9 m/s-)t-. @theexpertta.com - tracking id: 5188-75-0E-46-BB99-46077. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. -33% Part (a) What is the instantaneous velocity, in m/s, at t = 2.3 s? v = 9.492 - Correct! -33% Part (b) What is the instantaneous velocity, in m/s, at t = 3.6 s? v = 4.520 Correct! * 33% Part (c) What is the average velocity between t = 2.3 s and t = 3.6 s in m/'s? Grade Summary Vavg 7.59 Deductions 5% Potential 950% sin() cos( tan( 7 8 9 HOME Submissions Attempts remaining: 11 cotan( asin acos( E TA 4 5 6 (5% per attempt) atan() acotan( sinh( 1 2 3 detailed view tanh( END 5% cosh( cotanh() O Degrees O Radians BACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback[7%) Problem 11: A student launches a small rocket which starts from rest at ground level At a height h : 109 km: the rocket teaches a speed of U! = 291 m/s, Al that height; the rocket runs out of Fuel; so there is no longer any thrust propelling it, Take the positive direction to be upward, The drawing is not to scale, 7 33% Part (:1) Assuming constant acceleration; what is the rockefs acceleration; in meters per squared second; during the period from its launch until it runs out offuel\" u1 = 20.24 mfg; .t current 33% Part (b) After the rocket's engine turns o' at a height ofh : 2.09 km= it continues to move upward due to the velocity that it reached What is the roeket's acceleration: in meters per squared second, during the period Eton: engine shutoff until it returns to the ground? Ignore air resistance ug = - 9 El 09 : 79.810 mg? J Correct! $2 33% Part (c) Calculate the maximum height: in meters above ground level. that the rocket reaches. Grade Summary hmax = m Deductions Potential 72% Submissions Attempts remammg' _ per attempt) detailed view Degrees O Radians 44mm... Submit Hint l I give up! Hints: 7 for a deduction. Hints remaining: 7 Feedback: 7 for a deduction V'Xhen the rocket reaches height 1!: it is still moving up. No meaningful feedback available for the current submission (7%) Problem 12: Two cars are heading toward one another. The cars were initially at rest and separated by a distance of 1400 m. Car A is moving with an acceleration of 8 m/s-. Car B is moving with an acceleration of -9 m/s . Assume that they are on the x-axis. @theexpertta.com - tracking id: 5188-75-0E-46-BB99-46076. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. 25% Part (a) At what elapsed time, in seconds, do the cars meet? t= 12.84s

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