6 questions

Question 1 Use the following information to answer question 1 and 2 Not yet answered Marked out of 1.0 A basketball player catches a basketball, a force F is exerted on the baseball over time At. The basketball has a mass of 625 g and its velocity Remove flag changed from +4.00 m/s to + 2.00 m/s due to the force exerted on it by the player. The magnitude of the impulse that the player applied to the basketball is O a. 1.25 N's O b. 2.50 N'S O c. 1.25 x 102 N'S O d. 2.50 x 102 N'S Question 2 Using the information from question 1, if the player had applied half the force when she caught the ball, then the interval of time required to slow the ball would be Not yet answered O a. 4At Marked out of 1.0 O b. 2At Remove O c. _At flag O d. 1 At 4 4 Next pageQuestion 3 Not yet Use the following information to answer the next question. answered Marked out of 1.0 Force on an Object as a Function of Time Flag question 2 500 7 2 000 1 500 - Force (N) 1 000 500 2 5 Time (s) The area under the curve represents O a. work done on the object O b. the impulse encountered by the object O c. the object's displacement during the time the force is applied O d. the object's acceleration due to the net applied forceQuestion 4 Car 1 has a mass of 1.90 x 10"kg and is moving at a constant speed of 8.00 m/s. It strikes Car 2, which is at rest and has a mass of 1.30 x 10 kg. The cars lock together and continue to roll forward. They then collide and Not yet lock together with Car 3, which is at rest and has a mass of 1.50 x 10* kg. answered Marked out of 1.0 Before First Collision Flag question Car 1 Car 2 Car 3 V1 = 8.00 m/s V2 = 0 m/s V3 = 0 m/s Immediately After First Collision Car 1 / Car 2 Car 3 V 12 Immediately After Second Collision Car 1 Car 2 Car 3 V 123 Note: Vector arrows are not drawn to scale. The maximum speed of this three-car system, v123, immediately after the second collision is m/s. (Record your three-digit answer, do not include units)Question 5 The diagram below shows a train and car on a collision course. Not yet answered Marked out of 1.0 Flag question Train locomotive Train track m = 4.7 x 10* kg v = 12.0 m/s N WE Car m = 2.7 x 10' kg v = 27.0 m/s The momentum of the car -train system immediately before a collision would be Select one: O a. 5.69 x 10 kg.m/s, 7.36 North of east O b. 5.69 x 105 kg.m/s, 82.60 North of east O c. 6.40 x 10' kg.m/s, 7.360 North of east O d. 6.40 x 103 kg.m/s, 82.60 North of eastQuestion 6 Use the following information to answer the next question. Not yet answered The following lab set-up consists of two carts on a frictionless surface. Each end of the spring is attached to one of the carts and compressed. The two carts are then held together with a thin wire and are at rest. The Marked out of mass of Cart A is m and the mass of Cart B is 3.0 m. 1.0 Flag CART B question CART A Wire 3.0 m m Spring O After the wire is cut, Cart A moves to the left with a velocity of 1.2 m/s. and Cart B moves to the right with an unknown velocity. CART B CART A Cut Wire VII 3.0 m Spring 090000 Determine the speed of Cart B. O a. 0.40 m/s O b. 2.5 m/s O c. 1.2 m/s O d. 3.6 m/sEQUATIONS Kinematics Waves Atomic Physics Ad hi -di he Wave= W = hfo E =hf = At d = val - bar T = 2 m = T do dave = Av T = 2AND Ek de stop N = NO(4) + d = vi+ car ve = v.2+ 2ad n12 sine T = Quantum Mechanics and Nuclear Physics sine, AE = Amcz E = pc T2 n2 VI v = fx = V2 = M P = Dynamics A = h (1 - cose) mic(I a= - Inet F = Gmm2 f = (viv|Js 1 = d sine Trigonometry and Geometry 8 = Gm opposite Line 1 = xd sine = Ay nl hypotenuse M= - AX F, = -kx Fg g = m adjacent COSO = y = mx + b Electricity and Magnetism hypotenuse Momentum and Energy Fel = kq192 opposite Area 12 AV = AP tand = _ adjacent p = m Ek = =mv2 Rectangle = /w FAI = MAV E = 14 1 = 4 c' = a2+ 62 Ep = mgh Triangle = zab W = Fl la| cose Ep = -Kx2 Fe b Circle = 1/2 E = q IFm| = 1 B C sin A sin B sin C W = AE P = . W IFml = qVB c' = a2 + b2 - 2ab cos C Circumference E = AV Circle = 2ar