6. Suppose 15% of people do not own a calculator, 40% of people own one calculator, 40% own two calculators, and the remaining 5% own three calculators. Let X be the number of calculators that a randomly selected person owns. I = number of calculators 0 P(X = 1) = f(x) 0.15 0.40 0.40 0.05 (a) (3 points) What is the probability a person owns fewer than 3 calculators? (b) (3 points) What is the expected number of calculators that a person owns? (C) (3 points) What is E[X?? (d) (4 points) What is the standard deviation for the number of calculators that a person owns?