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6 The price P(X) of a car that is X years old is: P(x)=16630*(0.90)^X How much does the car cost is X = 3 years?

6 The price P(X) of a car that is X years old is:

P(x)=16630*(0.90)^X

How much does the car cost is X = 3 years?

How much does the car cost is X = 9 years?

Graph this function.

What year will the car reach $5000?

7 Solve the following equations for X:

a) e^(2X)=5

b) 20=6*e^(12.77*X)

c) 100=6*e^(-2*X)

8 Population P(t) equation follows:

P(t)= 298,710,000+10,000,000*LN (t).

Find t =1,10, and 20.

Graph this function.

9 Car Depreciation

New t =0 t=1 t=2 t=3 t=4 t=5

$38,000 36,600 32,400 28,750 25,400 21,200

Use the formula:

New=Old*e^(r*t)

Find the value of rate, r for a specific time, t.

Graph your function.

Compute the trendline and R^2.

0 1 2 3 4 5 6 7

10 Year 2006 2007 2008 2009 2010 2011 2012 2013

Sales 132.1 157.4 184.4 212.6 241.5 272.1 278.8 284.3

Let X =0 in 2006.

a) Build a model of the data by graphing it, using a trendline and R^2.

b) Estimate sales in 2015 and 2018.

c) Graph the exponential model from a).

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