61. A textile manufacturing process finds that on average, two flaws occur per every 50 yards of material produced. a. What is the probability of exactly two flaws in a 50- yard piece of material? b. What is the probability of no more than two flaws in a 50-yard piece of material? c. What is the probability of no flaws in a 25-yard piece of material?63. Airline travelers should be ready to be more flexible as airlines once again cancel thousands of flights this summer. The Coalition for Airline Passengers Rights, Health, and Safety averages 400 calls a day to help stranded travelers deal with airlines (http://seattlepi.com, July 10, 2008). Suppose the hotline is staffed for 16 hours a day. a. Calculate the average number of calls in a one-hour interval; 30-minute interval; 15-minute interval. b. What is the probability of exactly six calls in a 15-minute interval? c. What is the probability of no calls in a 15-minute interval? d. What is the probability of at least two calls in a 15-minute interval?The Poisson Distribution Example 5.10 [Returning to the Starbucks example] Ann believes that the typical Starbucks customer averages 18 visits over a 30-day month. Q2: What is the probability that a customer visits the chain five times in a 5-day period? u= 3 P(X = 5) = e-335 (0.0498)(243) = 0.1008 5! 120 A B C Expected number of Distribution Plot Poisson, Mean=3 0.25 1 visits in 5 days 3.00 =(18/30)*5 0.20 2 P(X=5) = 0.100819 =POISSON.DIST 5 B10) 0.1 Probability 0.1008 X mean 0.05 0: non-cumulative 0.00 XThe Poisson Distribution Example 5.10 Q3: What is the probability that a customer visits the chain no more than two times in a 5-day period? P(X