(6.2)8.2.

In a random sample of

six

mobile devices, the mean repair cost was

$65.00

and the standard deviation was

$11.50.

Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a

95%

confidence interval for the population mean. Interpret the results.

Question content area bottom

Part 1

The

95%

confidence interval for the population mean

is

(52.9352.93,77.0777.07).

(Round to two decimal places as needed.)

Part 2

The margin of error is

$enter your response here.

(Round to two decimal places as needed.)