66. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for a ball thrown straight up with an initial velocity of 15.0 m/s. Take the point of release to be yo = 0.78. The acceleration of a particle varies with time according to the equation a(() 2 pt 3 Initially, the velocity and position are zero. (a) What is the velocity as a function of time? (b) What is the position as a function of time?23'. A particle's acceleration is (4.0i + 3.03)!)'1f32 . At 1': CI, its position and velocity are zero. (a) What are the particle's position and velocity as functions of time? (b) Find the equation of the path of the particle. Draw the Jr and yaxes and sketch the trajectory of the particle; 48. A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60 above the horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20" to the horizontal. Relative to the coordinate system shown in the following figure, the equation of this straight line is y = (tan209)x - 109. Where on the hill does the projectile land? y = (tan 20')x - 109 75 m/s 60 20 300 m X