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66e25x + 96e-96x Find the horizontal asymptotes of the curve y = 18e25x - 6e-96x Note: Give the exact answer but not the decimal approximation(for
66e25x + 96e-96x Find the horizontal asymptotes of the curve y = 18e25x - 6e-96x Note: Give the exact answer but not the decimal approximation(for example, write 4/5 istead of 0.8). Answer: The equation of the horizontal asymptote which is above the x-axis is y = Va a sin (a) ? The equation of the horizontal asymptote which is below the x-axis is y =_ _ 60e95$ + 12127555 Find the vertical asymptote of the curve y = 178953: 1887539 Note: Give the exact answer but not the decimal approximation(for example' write 45 istead of 0.8). Write In for natural logarithm not logie. also remember to put brackets' for example, write ln(1!2) not In 12. Answer: The vertical asymptote is a}: Find the values of c and d that makes the following function continuous on t'. 2 c+d($ '81) ifaz 9 cw+d if$=9 Note: Give the exact answer but not the decimal approximationor example, write 45 istead of 0.8). Answer: The values of c and d are C
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