6a. The accelerator plates are 2.000 mm apart. Find the electric field Ea in accelerator such that the electron would approach the right plate with a velocity of 6.400 x 10 m/s in the x-direction. Show these key steps: i. By energy conservation, relate (symbolically) the electric field Ea with the charge e, mass me and final velocity Va of the electron. ii. Find the value of Ea in N/C. iii. What is the direction of Ea?The electron then passes through a small hole into another set of charged parallel plates. The electric eld Ed between the plates is -1000.N/C in the y-direction. When the electron is about to exit the deector, how much would the electron deviate from its original path? Upward or downward? Show these key steps: i. By considering the net force on the electron, nd the acceleration a of the electron in terms of the electric eld Ed, e and me ONLY. Find the value of a in mfsz. ii. Write relevant kinematic equations for the motion of the electron in terms of Ax, Av, t, v3 and a ONLY. Then determine the value of Av in m. 6c. Find the velocity of the electron as it exits the deflector in mls. What vertical position {in mm) will it land on a screen that is 10.0 cm apart? Vd=l , )mls AV = mm 6. Shown below is a cathode-ray tube (CRT). An electron is accelerated from rest by a set of parallel plates (accelerator). The electron will then be deflected by another set of parallel plates (deflector). Finally, the electron will land on a point on the screen. *For parts b and c, set y = 0 to be the original vertical position of the electron. 2.000 mm 1000. N/C 2.000 cm 10.00 cm (a) (b) (c) accelerator deflector screen