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6th Ques Question (2) - (7.5 marks) During last October, Haley Company had the following transactions, for sales to one of its customers October Sold

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6th Ques Question (2) - (7.5 marks) During last October, Haley Company had the following transactions, for sales to one of its customers October Sold merchandise $22.500 (Cost $ 13,500) with terms 3/10 1/30 October The customer returned some merchandise $ 2,500 because of incorrect sizes. This was agreed by Haley Company (cost is $ 1.800). 11th October Haley Company received cash from the customer from the goods sold on sth October Required: Prepare Journal entries to record the transactions above Haley Company uses a perpetual inventory system. Answer: Date Account Name Debit Credit CL Sauer Submit fotondrit Chelseve All Ato e alleen 6.1 cum prob one call two-ta 0.50 1.00 0.25 0.50 0.20 0.40 . 0.15 0.30 0.10 0.20 0.05 0.10 0.025 0.05 0.01 0.02 0.005 0.01 0.001 0.0005 0.002 0.001 1963 1386 1250 1.190 0.000 0.000 0.000 0 000 0 000 0.000 0.000 0.000 0.000 312 6.36 4541 3747 3078 1880 1836 1.833 1.41 1440 1000 0.816 0.765 0741 0727 0.718 0.711 0.703 700 3143 1134 1110 1.100 1415 2.900 47 0.100 1378 1.061 0.97 0.941 20 0.900 0.000 0.100 0.333 0.870 O.TO 0.873 0.870 0.868 0.000 1307 A bank branch located in a commercial district of a city had the business objective of improving the process for serving customers. The waiting time (defined as the time the customer enters the line until he or she reaches the teller window) of all customers during this hour is recorded over a period of a week. Data were collected from a random sample of 15 customers, and the results are organized as follows: 4.21 5.55 3.02 5.13 4.77 2.34 3.54 4.5 0.38 5.12 6.46 6.19 3.79 1) Calculate the Mean and t Table standard deviation for the given sample. 2) At the 0.05 level of significance, is there evidence that the population mean waiting time is less 1383 than 5 minutes? 3) What assumption about the population distribution is needed to conduct the t-test in 2.00 0.000 (2)? 4) As a customer asks the branch manager how long she can expect to wait. The branch manager replies, "Almost certainly not longer than 5 minutes." evaluate this statement 4501 5041 0.000 6314 2.000 2353 2132 2015 10 1 1.800 1.833 1.012 1796 1782 1770 1701 1753 1.140 1.740 1.734 1.372 123 1.000 108 0.000 0.007 1271 4303 3.182 2.776 2571 2447 2.305 2.300 2.202 2228 2200 2170 2160 2145 2131 2.120 2.110 2.100 4 10 11 12 13 10 15 10 17 10 10 OS 0.004 082 0.000 0.000 0.000 0 000 0.000 0.000 0.000 0001 0.000 1.350 1345 1.541 1337 1333 1.330 2.000 2.121 2.764 2.718 2.681 2.650 2.624 2.002 2.53 2.567 2.52 2.650 2.000 2518 2.500 no 0.668 0.000 an 1.30 TE 10 2.000 2.000 3.8 0.007 0.680 0.686 0.685 0.685 1064 100 63.66 318,31 636.82 9925 22 327 31.50 5.841 10215 12.04 604 7.173 8.610 4012 5.803 3707 5.200 5.00 3.490 5400 3355 3.250 4781 3109 4144 3.100 400 3055 1900 3.012 3.852 4221 2.77 3787 4140 2.947 3733 4073 2.921 36 4015 2.000 360 3005 3610 3922 3.670 2 MS 3.552 30 3527 3.810 2819 3.505 3.790 2 OP 3.485 3.76 2797 3.461 2787 3.450 3.725 2.779 3435 3.707 2.771 3421 3.60 2.763 3.400 3814 2.750 3.300 2.650 2750 as 3646 2704 1302 3550 2.000 3.400 26 3.105 3.410 2.620 3.11 3300 2.501 1000 3.300 2,670 3.000 3291 99%98%99.9% 1323 1321 2851 20 221 23 24 25 2.500 11 ON 0.802 0.01 0.00 0.850 050 0857 0850 OSO 0.856 0856 854 0.854 0151 0.848 1.079 1078 1074 1071 100 1.05 1000 1063 100 1050 1 05 1058 1057 1050 1055 toss 1.050 1.045 1043 1.042 1037 1034 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 ON 0854 27 1.325 2000 1717 2074 1.319 1310 2054 1.316 1708 2060 1:315 1.706 2.056 1314 1703 2.052 1313 1701 2048 1.311 1.000 2.046 1.310 1.00 2.042 1.03 164 2020 120 1871 2000 1 292 104 1900 1200 1000 1994 1640 102 1.200 1.645 1900 BON 90% 95% Confidence Level 0.664 0.663 0.663 0.683 0.681 0670 07 0.577 0.615 0614 SON 30 40 001 2412 245 249 2.473 2.457 2462 2.457 2493 2.300 2374 24 2.330 2320 100 1000 0.845 0.042 0.842 60 Z 70

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