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7. [-/10 Points] DETAILS MY NOTES ASK YOUR TEACHER Suppose you have 8 populations, and you want to compare their population means. You take a

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7. [-/10 Points] DETAILS MY NOTES ASK YOUR TEACHER Suppose you have 8 populations, and you want to compare their population means. You take a sample of size 22 from each population. You find that the Corrected Total Sum of Squres is 10280, while the Sum of Squares for error is 9540. a. Complete the following ANOVA Table TABLE 1 Source Pvalue Model Error 9540 168 Corrected Total 10280 Hint1: SSCorrectedTotal=SSModel+SSError and ofCorrectedTotal=ofModel+dfError=(t-1)+(n-t)=n-1 where t is the number of populations compared and n is the total number of observations. Hint2: MS=SS/df and F=MSModel/MSError Hint3: pvalue is the probability above the F value with numerator of, df1=t-1 and denominator df, df2=n-t. Please follow the instructions in this pdf document to calculate the pvalue using F distribution. please right click here to download the pdf file. b. Is the null hypothesis in ANOVA rejected? Use a=0. 10. O yes O no . Suppose that the sample means from the first two pop are 98 and 100, respectively. Construct a 95 ation means using Fisher's LSD. )(Note: you will compute this by hand using the given information in t e question and part (3). The answer e is calculated. Use the given order. I mean 98-100) Fisher's LSD Example: the sample means are 20 and 30 for the data with sample sizes 10 each (=n1=n2), and MSE from ANOVA is 2.2942 then 90% C.I for group1-group2 in the example of 5 (=t) groups really compared with ANOVA is (20-30) + tcritical*sqrt(MSE)*sqrt(11+12)=(20-30) # 1.6794274*sqrt(2.2942)*sqrt(1/10+1/10)=( -11.1376, -8.86239) where tcritical=1.6794274 is calculated with total data 5*10=50 so dferror=totaldata-t=50-5=45 and the probability below the tcritical being 0.95 and above 0.05 because you are 90% confident. please click here for the pdf file explaining JMP steps to obtain the tcritical value

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