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7) 10 r=7+7 sin e -10 (7+7sin 0) do = 49 j (1+ sin0} d0 ...6) Now j (1+ sinof do = /(sin(0) +
7) 10 r=7+7 sin e -10 (7+7sin 0) do = 49 j (1+ sin0} d0 ...6) Now j (1+ sinof do = /(sin(0) + 1) do = / (sin(@) + 2sin(@) + 1) de = [ sin"(0) do + 2 /sin() do + f1 do sin(20) + 8 cos(0) - 60 Hence, sin o do sin(20) + 8 cos(@) 60 From (i) 3x = 49 147 The required Area is a= 49 (1+ sin do 2
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Elementary Statistics
Authors: Mario F. Triola
12th Edition
0321836960, 978-0321836960
