$7\mathrm{.}8084\frac{g}{mL}0\mathrm{.}2mL=g$

$93\mathrm{.}4\frac{g}{mL}30.mL=g$

$366\mathrm{.}4$mol$44\mathrm{.}180L=\frac{\text{m}\text{o}\text{l}}{L}$