7) Approximately 15% of all people are left-handed. Consider a grouping of SIX people. (Use Table below)

1. State the random variable.
2. Write the probability distribution: P(x) for x = 0 to 6 (you can use software)
3. Use the long binomial equation: P (k) = {n! / [k! *(n-k)!]} * pk * q(n-k)
4. The P(x) values SHOULD be the SAME, whether from the Software or the Equation.
5. Draw a histogram.
6. Describe the shape of the histogram (is it skewed and if so + or - skew).
7. Find the mean using = np.
8. Find the variance using 2 = npq.
9. Find the standard deviation = SQRT(npq)

Are the means, variance, and standard deviations from the Table below different from the binomial approximations? How so? Any reason for this you can think of?

x (Left Handed)	P(x) from SOFTWARE	P(x) from Calculation	x*P(x)	(x-mean)	(x-mean)^2	(x-mean)^2 * P(x)
0
1
2
3
4
5
6
Sum	1	1
	^ mean		^ variance
		Std Deviation = _________