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7) Find the equation of the line tangent to the function at the point (3, 1). 2(x2 + y/2) = 25(x2 - 12)2 8) Find

7) Find the equation of the line tangent to the function at the point (3, 1). 2(x2 + y/2)" = 25(x2 - 12)2 8) Find the equation of the line tangent to the function at the point (1, 1). 12. (12 - 4)? =x2. (x2 -5)

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