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7. In a random sample of 60 refrigerators, the mean repair cost was $150.00 and the standard deviation was $15.50. a) Construct a 99% confidence

7. In a random sample of 60 refrigerators, the mean repair cost was $150.00 and the standard deviation was $15.50.

a) Construct a 99% confidence interval for the population mean repair cost. Interpret the results.

b) Calculate the two standard deviation interval and discuss the difference in meaning from it and the confidence interval from part a.

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