(7%) Problem 6: On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck d = 1.9 mi in front of him. That truck is moving in the same direction at v2 = 34 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval At. The smallest acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction. Refer to the figure below. U2 V1 OOO OC c damsinn -inn A 11% Part (a) Enter an expression, in terms of defined quantities, for the distance, Ax2, traveled by the truck during the time interval At. Ar2 = -1 Grade Summary Deductions Potential 100% a At Ax2 7 8 9 HOME Submissions A b d 4 5 6 Attempts remaining: 40 h i 1 2 3 (0% per attempt) detailed view m n P 0 END S t V 1 VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 3% deduction per feedback. 4 11 % Part (b) Enter an expression for the distance, Ax, traveled by the car in terms of v1, v2 and a. 4 11% Part (c) Enter an expression for the acceleration of the car, a, in terms of v1, V2, and At. A 11% Part (d) Enter an expression for Ax, in terms of Ax2 and d when the driver just barely avoids collision. 4 11% Part (e) Enter an expression for Ax, in terms of v1, V2, and At. 4 11% Part (f) Enter an expression for At in terms of d, v1, and v2. 4 11% Part (g) Calculate the value of At in hours. 4 11% Part (h) Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2. 11% Part (i) Calculate the value of a in meters per second squared