7:40 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Question...

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7:40 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Question 1 Done < > 0/1 pt 4 Details Run a regression analysis on the following bivariate set of data with y as the response variable. x y 12.2 31.8 37 1 31.5 13.6 5.7 28 38.8 5 21.6 11.2 12.3 25.6 12.9 7.9 12.3 21.9 10.8 23.6 41.5 12.1 Verify that the correlation is significant at an = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 14.4 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 2 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 102). You obtain the regression equation y = -1.908x +49.186 with a correlation coefficient of r = -0.267 (which is significant at a = 0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 160 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 3 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 82). You obtain the regression equation y = 4.278x + 0.981 4.278x0.981 with a correlation coefficient of r = 0.817 (which is significant at a = 0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 60 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:40 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done o Question 4 0/1 pt 4 Details > Based on the data shown below, calculate the regression line (each value to at least two decimal places) y: = X y 4 20.82 5 18.65 6 20.68 7 22.71 8 22.74 9 24.97 10 24.7 11 29.03 12 29.86 13 29.09 14 29.02 15 30.05 16 | 34.28 17 | 34.91 18 34.44 19 36.27 Submit Question X + myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 5 0/1 pt 4 Details < > A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.337 b=20.318 r=0.506944 r=-0.712 Use this to predict the number of situps a person who watches 9 hours of TV can do (to one decimal place) Submit Question AA myopenmath.com 7:40 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 6 0/1 pt 4 Details < > The line of best fit through a set of data is y = 43.322 + 1.635x According to this equation, what is the predicted value of the dependent variable when the independent variable has value 100? y = place. Submit Question AA Round to 1 decimal myopenmath.com 1 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 7 0/1 pt 4 Details < > Run a regression analysis on the following bivariate set of data with y as the response variable. y 71.4 23.7 80.7 34.1 69.2 16 75 25.1 77.5 26.7 79.5 36.1 64.6 10.9 80 37 82 39.4 69.7 14.1 72 25.5 Verify that the correlation is significant at an = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 30.3 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 8 0/1 pt 4 Details < > The line of best fit through a set of data is y = -17.724 +1.787x According to this equation, what is the predicted value of the dependent variable when the independent variable has value 40? y = place. Submit Question AA Round to 1 decimal myopenmath.com 1 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 9 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to at least two decimal places) y = X y 1 13.91 2 15.92 3 20.23 4 23.04 5 23.55 6 25.86 7 30.37 8 33.98 9 33.49 10 37.7 11 42.61 12 43.62 13 46.13 14 48.14 15 52.05 16 55.06 Submit Question X + AA myopenmath.com 1 7:40 ASSESSMent Score: 0/19 0/19 answered Progress saved Done 0 all 39 Question 10 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to two decimal places) y = y 4 44.58 5 41.76 6 38.04 7 38.22 8 33.9 9 35.28 10 31.56 11 27.74 12 27.12 13 26.5 14 21.88 15 22.96 16 19.34 17 16.32 18 15.6 Question Help: Video Submit Question X + myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 11 0/1 pt 4 Details < > Run a regression analysis on the following bivariate set of data with y as the response variable. y 18.8 61.1 37.4 60.4 34.9 65.9 26.5 68.1 23.9 62.7 12.9 71.4 44.9 49.4 31.7 58.3 41 56.6 42.3 49 54.6 49.5 Verify that the correlation is significant at an = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 52.6 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 7:41 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 12 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 12). With 49.2 and y = 77.4, you obtain the regression equation = y = 2.146x 28.183 with a correlation coefficient of r = 0.085. You want to predict what value (on average) for the response variable will be obtained from a value of x = 190 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 13 0/1 pt 4 Details < > The line of best fit through a set of data is y= 0.3262.014x According to this equation, what is the predicted value of the dependent variable when the independent variable has value 80? y = place. Submit Question AA Round to 1 decimal myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 14 0/1 pt 4 Details < > A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.019 b=23.032 r=0.416025 r=-0.645 Use this to predict the number of situps a person who watches 1 hours of TV can do (to one decimal place) Submit Question AA myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 15 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 33). With 42.7 and y = 72.2, you obtain the regression equation x = y = 0.883x + 34.496 with a correlation coefficient of r = 0.99. You want to predict what value (on average) for the response variable will be obtained from a value of x = 150 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 16 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to two decimal places) y = X y 4 11.5 5 9.65 6 10.5 7 12.65 8 11.7 9 10.05 10 12.6 11 12 12.95 12.9 13 || 9.95 14 10.2 Question Help: Video Submit Question AA X + myopenmath.com 1 7:41 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 17 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to at least two decimal places) y = X y 4 12.68 5 16.1 6 18.52 7 19.64 8 20.36 9 24.48 10 27.4 11 30.22 12 29.94 13 | 30.86 14 34.78 15 36.1 Submit Question AA X + myopenmath.com 1 7:41 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 18 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 113). You obtain the regression equation y = 1.645x - 31.608 with a correlation coefficient of r = -0.749 (which is significant at a = 0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 110 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:41 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 19 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 78). With x = 53.3 and y = 53.4, you obtain the regression equation y= -4.136x + 273.849 with a correlation coefficient of r = -0.098. You want to predict what value (on average) for the response variable will be obtained from a value of x = 190 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:40 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Question 1 Done < > 0/1 pt 4 Details Run a regression analysis on the following bivariate set of data with y as the response variable. x y 12.2 31.8 37 1 31.5 13.6 5.7 28 38.8 5 21.6 11.2 12.3 25.6 12.9 7.9 12.3 21.9 10.8 23.6 41.5 12.1 Verify that the correlation is significant at an = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 14.4 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 2 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 102). You obtain the regression equation y = -1.908x +49.186 with a correlation coefficient of r = -0.267 (which is significant at a = 0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 160 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 3 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 82). You obtain the regression equation y = 4.278x + 0.981 4.278x0.981 with a correlation coefficient of r = 0.817 (which is significant at a = 0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 60 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:40 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done o Question 4 0/1 pt 4 Details > Based on the data shown below, calculate the regression line (each value to at least two decimal places) y: = X y 4 20.82 5 18.65 6 20.68 7 22.71 8 22.74 9 24.97 10 24.7 11 29.03 12 29.86 13 29.09 14 29.02 15 30.05 16 | 34.28 17 | 34.91 18 34.44 19 36.27 Submit Question X + myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 5 0/1 pt 4 Details < > A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.337 b=20.318 r=0.506944 r=-0.712 Use this to predict the number of situps a person who watches 9 hours of TV can do (to one decimal place) Submit Question AA myopenmath.com 7:40 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 6 0/1 pt 4 Details < > The line of best fit through a set of data is y = 43.322 + 1.635x According to this equation, what is the predicted value of the dependent variable when the independent variable has value 100? y = place. Submit Question AA Round to 1 decimal myopenmath.com 1 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 7 0/1 pt 4 Details < > Run a regression analysis on the following bivariate set of data with y as the response variable. y 71.4 23.7 80.7 34.1 69.2 16 75 25.1 77.5 26.7 79.5 36.1 64.6 10.9 80 37 82 39.4 69.7 14.1 72 25.5 Verify that the correlation is significant at an = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 30.3 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 8 0/1 pt 4 Details < > The line of best fit through a set of data is y = -17.724 +1.787x According to this equation, what is the predicted value of the dependent variable when the independent variable has value 40? y = place. Submit Question AA Round to 1 decimal myopenmath.com 1 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 9 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to at least two decimal places) y = X y 1 13.91 2 15.92 3 20.23 4 23.04 5 23.55 6 25.86 7 30.37 8 33.98 9 33.49 10 37.7 11 42.61 12 43.62 13 46.13 14 48.14 15 52.05 16 55.06 Submit Question X + AA myopenmath.com 1 7:40 ASSESSMent Score: 0/19 0/19 answered Progress saved Done 0 all 39 Question 10 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to two decimal places) y = y 4 44.58 5 41.76 6 38.04 7 38.22 8 33.9 9 35.28 10 31.56 11 27.74 12 27.12 13 26.5 14 21.88 15 22.96 16 19.34 17 16.32 18 15.6 Question Help: Video Submit Question X + myopenmath.com 7:40 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 11 0/1 pt 4 Details < > Run a regression analysis on the following bivariate set of data with y as the response variable. y 18.8 61.1 37.4 60.4 34.9 65.9 26.5 68.1 23.9 62.7 12.9 71.4 44.9 49.4 31.7 58.3 41 56.6 42.3 49 54.6 49.5 Verify that the correlation is significant at an = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 52.6 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 7:41 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 12 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 12). With 49.2 and y = 77.4, you obtain the regression equation = y = 2.146x 28.183 with a correlation coefficient of r = 0.085. You want to predict what value (on average) for the response variable will be obtained from a value of x = 190 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 13 0/1 pt 4 Details < > The line of best fit through a set of data is y= 0.3262.014x According to this equation, what is the predicted value of the dependent variable when the independent variable has value 80? y = place. Submit Question AA Round to 1 decimal myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 14 0/1 pt 4 Details < > A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-1.019 b=23.032 r=0.416025 r=-0.645 Use this to predict the number of situps a person who watches 1 hours of TV can do (to one decimal place) Submit Question AA myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 15 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 33). With 42.7 and y = 72.2, you obtain the regression equation x = y = 0.883x + 34.496 with a correlation coefficient of r = 0.99. You want to predict what value (on average) for the response variable will be obtained from a value of x = 150 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:41 .l 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 16 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to two decimal places) y = X y 4 11.5 5 9.65 6 10.5 7 12.65 8 11.7 9 10.05 10 12.6 11 12 12.95 12.9 13 || 9.95 14 10.2 Question Help: Video Submit Question AA X + myopenmath.com 1 7:41 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 17 0/1 pt 4 Details < > Based on the data shown below, calculate the regression line (each value to at least two decimal places) y = X y 4 12.68 5 16.1 6 18.52 7 19.64 8 20.36 9 24.48 10 27.4 11 30.22 12 29.94 13 | 30.86 14 34.78 15 36.1 Submit Question AA X + myopenmath.com 1 7:41 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 18 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 113). You obtain the regression equation y = 1.645x - 31.608 with a correlation coefficient of r = -0.749 (which is significant at a = 0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 110 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1 7:41 ... 39 Unit 8 Section 10.1: Linear Regression Assessment Score: 0/19 0/19 answered Progress saved Done 0 Question 19 0/1 pt 4 Details < > You run a regression analysis on a bivariate set of data ( n = 78). With x = 53.3 and y = 53.4, you obtain the regression equation y= -4.136x + 273.849 with a correlation coefficient of r = -0.098. You want to predict what value (on average) for the response variable will be obtained from a value of x = 190 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.) Submit Question AA myopenmath.com 1