8. [033/416 Points] DETAILS PREVIOUS ANSWERS ASWSBE149.E.029o You may need to use the appropriate appendix table or technology to answer this question. l MV NOTES ll ASK VOURTEACHER H PRACTICE ANOTHER On its municipal website, the city of Tulsa states that the rate it charges per 5 ch of residential water is $11.62. How do the residential water rates of other U.5. public utilities compare to Tulsa's rate? The data shown below (s) contains the rate per 5 ch of residential water for 42 randomly selected U.s. cities. 10.58 9.28 11.9 6.6 12.52 14.53 15.55 10.22 14.5 16.28 17.7 19.28 18.08 12.95 15.9 17 45 15.74 14.9 19.01 18.09 15 18.52 15,15 25.95 22.42 22.55 21.05 23.55 19.15 23.8 19.35 23.85 27.9 27.15 27.24 27.09 24 76 37.95 25.51 39.11 29.55 41.75 (a) Formulate hypotheses that can be used to determine whether the population mean rate per 5 ccr of residential water charged by us public utilities differs from the 521.62 rate charged by Tulsa. (Enter i: for s as needed.) (b) What is the test statistic far your hypothesis test in part (a)? (Round your answer to three decimal places.) X (c) A! o : 0.05, can your null hypothesis be rejected? what is your conclusion? Value for your hypothesis test in part (a)' (Round your answer to four decimal places.) (Q Do not reJect H0. The mean rate per 5 CCF of residential water throughout the united States does not differ signicantly from the rate per 5 CCF of residential water in Tulsa. O Reject Ho. The mean rate per 5 CCF of residential water throughout the United states does not differ significantly from the rate per 5 (IF of residential water in Tulsa. 0 Do not reject Ho. The mean rate per 5 cos of residential water throughout the united states differs significantly from the mte per 5 ca= or residential water in Tulsa. O Reject Ho. The mean rate per 5 ch of residential water throughout the United states differs signicantly from the rate per 5 CCF of residential water in Tulsa. (d) Repeat the preceding hypothesis test using the critical value approach. state the null and alternative hypotheses. (Enter !: for e as needed) H: 2162 X Find the value of the test statistic. (Round your answer to three decimal places.) I: (d) Repeat the preceding hypothesis test using the critical value approach. State the null and alternative hypotheses. (Enter != for * as needed.) H0: 21.62 X Ha: Find the value of the test statistic. (Round your answer to three decimal places.) E State the critical values for the rejection rule. Use a = 0.05. (Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.) test statistic s 3' test statistic 2 3' State your conclusion. ('3 Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ signicantly from the rate per 5 CCF of residential water in Tulsa. O Reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa. 0 Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa. \\J Reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa