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8 = 1.386 PL P the stress distribution 5 (x) = AE in the bar: A 4 (1) A(x) = A (1-7) 2L L
8 = 1.386 PL P the stress distribution 5 (x) = AE in the bar: A 4 (1) A(x) = A (1-7) 2L L 0.5L 0.75L == 0.25 2 (a) (b) (a) tapered axial bar, (b) one-element model, (c) two-element model 3 (c) 78 A 58 -A 84
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Engineering Mechanics Statics
Authors: R. C. Hibbeler
12th Edition
136077900, 978-0136077909
