$8\_2$ Figure on the right is an in vitro fluid flow model of

the human urethra. $($From Bush, M$.$B$.$ et al$.,$ J$.$ Biomech.,

$30,967,1997.)$ They obtained the following data shown

in the table from their experimental model.

The pressure difference represents the reservoir head $(H)$

shown in the figure plus the additional $h=2cm$ from the

bottom of the reservoir to the exit of the urethra. From

Bernoulli Eq$.$ we have:

$H=\frac{V_2^2}{2g}+\frac{h_f}{g}-h,h_f=\frac{fL{V}_2^2}{2d}+\mathrm{.}225V_2^2,$

where $\mathrm{.}225$ is calculated from the minor loss coefficient.

If we sub. $V_2=\frac{4Q}{d^2}$ into the equation, we have $H=\frac{16Q^2}{2{}^2{D}^{4}g}+\frac{1}{g}(\frac{16Q^2}{{}^2{D}^4})(\frac{fL}{2D}+\mathrm{.}225)-h(1).$ If $D=3\mathrm{.}5mm,$

and $f=4[0\mathrm{.}0791R{e}^2-0\mathrm{.}25],L=4cm,D=3\mathrm{.}25mm,=1\frac{g}{c}{m}^3,$ please use Matlab to graphically

compare Bernoulli equation's prediction with the experimental data given in the table. $($Hint: result should