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8. The height of an object at time t, thrown straight up from ground level with an initial velocity of 48 feet per second, is

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8. The height of an object at time t, thrown straight up from ground level with an initial velocity of 48 feet per second, is h(t) = 48t - 16t2. (a) What is the maximum height attained? (b) At t = 1, how fast is the object moving, and in what direction? (c) How long does it take for the object to return to the ground

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