8. Vertical motion, t>t_thrust We also need to calculate vertical position in the second segment (after engine burnout). but the For the second segment ft > t thrust (when the engine is no longer firing) the vertical acceleration is just - initial position and velocity would be the final vertical position and velocity from the first segment. The final vertical position from the first segment can be calculated from y = (1/2)aythrust The final velocity from the first segment can be calculated from Uy, l = 0o + ayl hrust where Do = 0 m/s for the first segment. Now calculate yi and vy1 , the initial position and velocity respectively for the second segment. In [ ]: y = .5*(ay)*t_thrust**2 vyl = 8+(ay)*t_thrust Calculate the vertical positions in the second segment. Our expression for position would be y = y + 0.11 - Ithrust) + (1/2)ay.21 -Irws' based on initial position yi, initial velocity 0y.l. acceleration ay.2 and segment starting time thrust. The acceleration ay.2 is just gravity (-9). So calculate the acceleration ay2 then evaluate vertical (y) position in the second segment. Don't forget use use the brackets [t>t_thrust) to restrict the calculation to the subsets of y and t corresponding to times after thrust burnout. In []: Nay2 = y[t > t_thrust] =