$9\mathrm{.}24$ The densities of $H_{2}O$ and $C{H}_{3}OH$ at $25C$ and $1$atm are $0\mathrm{.}99705$ and $0\mathrm{.}78706\frac{g}{c}{m}^3,$ respectively. For solutions of these two compounds at $25C$ and $1$atm,${}_{\text{m}\text{i}\text{x}}\frac{V}{n}-$vs$.-x_{H_{2}O}$ data are:

$\backslash$table$[[\frac{{}_{\text{m}\text{i}\text{x}}\frac{V}{n}}{c\frac{m^3}{m}ol},-0\mathrm{.}34,-0\mathrm{.}60,-0\mathrm{.}80],[x_{H_{2}O},0\mathrm{.}1,0\mathrm{.}2,0\mathrm{.}3],[\frac{{}_{\text{m}\text{i}\text{x}}\frac{V}{n}}{c\frac{m^3}{m}ol},-{0\mathrm{.}94}_5,-1\mathrm{.}01,-0\mathrm{.}98],[x_{H_{2}O},0\mathrm{.}4,0\mathrm{.}5,0\mathrm{.}6],[\frac{{}_{\text{m}\text{i}\text{x}}\frac{V}{n}}{c\frac{m^3}{m}ol},-0\mathrm{.}85,-{0\mathrm{.}61}_5,-0\mathrm{.}31],[x_{H_{2}O},0\mathrm{.}7,0\mathrm{.}8,0\mathrm{.}9]]$

Use the intercept method $($Fig$.9\mathrm{.}8)$ to find the partial molar volumes at $x_{H_{2}O}$ values of $(a)0$; $($b$)0\mathrm{.}4$; $($c$)0\mathrm{.}6.$