9. Expand log.r in the power of I - I and hence evaluate log, 0.2. In Chan that sinell 1 rost) is a maximum when I = 1. q. f (x ) = 10gex xx20 X- 1=0 2=1 x5205 f ( x ) =20 Loos = > f " ( x ) = _ x - 2 f' ( 1 ) = 1 f " ( 1 ) = -1 f " ( x ) = 2x - 3 f " ( 1 ) = 2 for ( x ) = - 62-4 f " (1 ) = - 6 091-82034 X 2035 f ( x ) = f ( 0) + ( x- 1 ) f ( 1 ) + ( x -1 )2 2- X203 5+ 3 2038 - f " ( 1 ) + ( 2 - 1 ) 2 ! 3 1 f " () s... = (14+ X205 ( 1 -X 205 5) = (X-1) _ ( 2-1)2 + ( x- 1 ) 3 2 - . . . . 3 0=14X290 1- = X203 log (0.2) - (0.2-1 ) - (0.2-1)2 (0.2-1)(10:2-1) * 2 4 = -0.8 - (-0.8)" (-0.8)' (-0-87" 2 3 4 = - 0.8 - 0 .64 _ 0. 512 0. 4096 2 = -0.8 - 0.32 - 0.17 - 0.1024 = - 0. 2076