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9. Let Q1 be the number of combinations of length 10 of 21 distinct elements. Let Q = ln(3 + |Q1|). Then T = 5
9. Let Q1 be the number of combinations of length 10 of 21 distinct elements. Let Q = ln(3 + |Q1|). Then T = 5 sin2(100Q) satisfies: (A) 0 T < 1. (B) 1 T < 2.
(C) 2 T < 3. (D) 3 T < 4. (E) 4 T 5.
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Bent Functions Results And Applications To Cryptography
Authors: Natalia Tokareva
1st Edition
0128025557, 9780128025550
