(9%) Problem 6: Consider the circuit diagram in the figure. R 2.5- 1-18 V 4/2 m 0.5 a E = 45 V R ww 6.02 0.5 R 1.5 0 = 50% Part (a) What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? 50% Part (b) If the current through the middle part of the loop is I = 4.75 amps, what is the current through the top loop, 12, in amps? 12 = (9%) Problem 9: An uncharged capacitor with C = 27 F and a resistor with R = 75 are connected in series with a battery of = 7.5 V. Randomized Variables C=27 F R = 7592 8 = 7.5 V R x = A 25% Part (a) Express the time constant 7 in terms of R and C. 25% Part (b) Calculate the numerical value of t in s. T = Q = 25% Part (c) Express the maximum charge Q on the capacitor in terms of C and . 25% Part (d) Calculate the numerical value of Q in C. Q