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9251AM Mon Oct 15 co. 3' 4? 73% - . ii cvws.ic|oudcontent.com 12. When the astronaut enters the ISS (International Space Station), she is in
9251AM Mon Oct 15 co. 3' 4? 73% - . ii cvws.ic|oudcontent.com 12. When the astronaut enters the ISS (International Space Station), she is in "free fall,\" where the only force acting on her is the force of gravity applied by the Earth. What happens to her true weight and her apparent weight as she enters the ISS? Explain. (You may want to reference p. 227-228 of the textbook to help you.) 1 5/2 When an astronaut enters the International Space Station (ISS), she is essentially in free fall around the Earth. This means that the only force acting on her is the force of gravity, which is still pulling her towards the center of the Earth. However, because she and the ISS are both falling towards the Earth at the same rate, it gives the illusion of See Lesson 5, P9 weightlessness or zero gravity. , _ Her true weight is slightly less. can you see why? \"Apparent Weight\" In terms of her true weight, it does not change as she enters the ISS. She still has the same mass and the same and 9227228 0f gravitational attraction to the Earth as she did before entering the ISS. However, her apparent weight does change textbook because there is no longer a force from a surface pushing back against her to counteract the force of gravity. In other words, her apparent weight is zero when she is in free fall inside the ISS. This is because she is accelerating towards the Earth at the same rate as the ISS, so there is no force pushing against her. As a result, she feels weightless even though she still has mass and weight due to the force of gravity. 13. What is the mass of a person accelerating downward at -5.45 m/s2 if they are standing on a scale that reads 236 N? F3m\" Fnel=Fg+FN QEE'N T. (Pic-5N5 (\"'52) 0.5/2 m: 23M\" CS-MSm/sa') X (-9.81m/s2) m 3 413.3\
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