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9:51AM Mon Oct 16 . . . -73% cvws.icloud-content.com 5 of 8 5 Physics 20: Mrs. Tyler Assignment 7 7. Use the following information to
9:51AM Mon Oct 16 . . . -73% cvws.icloud-content.com 5 of 8 5 Physics 20: Mrs. Tyler Assignment 7 7. Use the following information to answer parts a-c. You may want to reference the page "Simple Pulleys" (Lesson 5 Page 8) from your course for this question. A student sets up a Fletcher's Trolley, where Block 1, on the table, has a mass of 0.450 kg and Block 2, suspended off the side of the table, has a mass of 0.766 kg. Assume the mass of the rope and friction are negligible. a) Calculate the acceleration of the system. Show all work starting with free- 1/4 (4 body diagrams and net force equations for each block. Vet force Equation : Block 2 Block ! 31 : Fnet , 1=0 0. 450 0.766 Fweight!) = mixg = 0. 450kg x 9.8/ ms = 4.4IN fromdil = fweight ,1 = 4 . WIN Please label the forces here and show direction. Your 62 : Fnex 1 2 = flennon Force is the wrong direction fungus , 2 = M2 x 8 = 0. 76bly * 9.8/ m /3 ? = 7. SIN for Block 1. Please review Fletcher's Trolley. Accetration : Fnet = M, XS Flenwon = mz* 9 MIXa = O 9. 81 M /S 2 a = (maxs ) mr a = - (m2g)/(m1+m2) See Lesson 5, P8 "Simple Pulleys" 9 :8 (1) b) Calculate the magnitude of the tension in the rope. Show all work. Fnet , 2 = mana mia = Ft1 See Lesson 5, P8 "Simple Pulleys ftension - 1.510 = 0. 766 kg x 9.81m/s 2 flenton - 7.5 1 1 = 7. son Flewon = 15.0IN ADLC All Rights Reserved (2019)
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