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9n3 - 5n2 +13 Use the limit comparison test to determine whether > an = 9 + 4n4 converges or diverges. n=13 n=13 (a) Choose

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9n3 - 5n2 +13 Use the limit comparison test to determine whether > an = 9 + 4n4 converges or diverges. n=13 n=13 (a) Choose a series >bn with terms of the form by = 1 and apply the limit comparison test. Write your answer as a fully simplified fraction. For n 2 13, n=13 lim an lim n-too bn n-+00 (b) Evaluate the limit in the previous part. Enter co as infinity and -co as -infinity. If the limit does not exist, enter DNE. lim an = n-too bn (c) By the limit comparison test, does the series converge, diverge, or is the test inconclusive? |Inconclusive v

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