Question: A 0 . 3 5 - k resistor and 4 2 0 - mH inductor are connected in series to a Vrms = 1 2

A 0.35-k resistor and 420-mH inductor are connected in series to a Vrms =120 V AC power source oscillating at a frequency of f =60 Hz. The voltage as a function of time is given by
V = V0cos(t),
where V0 is the amplitude, is the angular frequency.
Holmes,Tim-trh5605@psu.edu
trh5605@psu.edu0P65-85-39-40-BD61-52483
- Part (a)
What is the amplitude of the source voltage, in volts?
V0=169.7169.7Correct!
- Part (b)
Enter an expression for the impedance of the circuit in terms of R, L, f, and .
Z =((R)2+(2fL)2)Correct!
- Part (c)
Enter an expression for the tangent of the phase constant of the circuit in terms of R, L, f, and .
tan =2fL/RCorrect!
- Part (d)
Assume the time dependence of the source voltage is given by V = V0cos377t, where the amplitude V0 is what you calculated in part (a) and the angular frequency is (2)60 rad/s 377 rad/s. Select the correct expression for the current in the circuit.
Correct!
- Part (e)
Find the current in the circuit, in amperes, at time t =4.1 s.
I =0.41200.4120Correct!
- Part (f)
Find the voltage drop across the resistor, in volts, at time t =4.1 s.
VR =144.2144.2Correct!
Part (g)
Find the voltage drop across the inductor, in volts, at time t =4.1 s.

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