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A 0.00415-kg bullet traveling horizontally with a speed of 1.00 x 10 m/s enters a 17.5-kg door, embedding itself 16.0 cm from the side

A 0.00415-kg bullet traveling horizontally with a speed of 1.00 x 10 m/s enters a 17.5-kg door, embedding

A 0.00415-kg bullet traveling horizontally with a speed of 1.00 x 10 m/s enters a 17.5-kg door, embedding itself 16.0 cm from the side opposite the hinges as in the figure below. The 1.00-m-wide door is free to swing on its hinges. Hinge (a) Before it hits the door, does the bullet have angular momentum relative to the door's axis of rotation? O Yes O No (b) Is mechanical energy conserved in this collision? Answer without doing a calculation. O Yes O No (c) At what angular speed does the door swing open immediately after the collision? (The door has the same moment of inertia as a rod with axis at one end.) rad/s (d) Calculate the energy of the door-bullet system. (Enter the kinetic energy of the door-bullet system just after collision.) Determine whether the energy of the door-bullet system is less than or equal to the kinetic energy of the bullet before the collision. O less than O equal

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a Yes the bullet has angular momentum relative to the doors axis of rotation before it hits the door The bullets velocity is horizontal so it has no v... blur-text-image

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