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A 0.00415-kg bullet traveling horizontally with a speed of 1.00 x 10 m/s enters a 17.5-kg door, embedding itself 16.0 cm from the side
A 0.00415-kg bullet traveling horizontally with a speed of 1.00 x 10 m/s enters a 17.5-kg door, embedding itself 16.0 cm from the side opposite the hinges as in the figure below. The 1.00-m-wide door is free to swing on its hinges. Hinge (a) Before it hits the door, does the bullet have angular momentum relative to the door's axis of rotation? O Yes O No (b) Is mechanical energy conserved in this collision? Answer without doing a calculation. O Yes O No (c) At what angular speed does the door swing open immediately after the collision? (The door has the same moment of inertia as a rod with axis at one end.) rad/s (d) Calculate the energy of the door-bullet system. (Enter the kinetic energy of the door-bullet system just after collision.) Determine whether the energy of the door-bullet system is less than or equal to the kinetic energy of the bullet before the collision. O less than O equal
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a Yes the bullet has angular momentum relative to the doors axis of rotation before it hits the door The bullets velocity is horizontal so it has no v...Get Instant Access to Expert-Tailored Solutions
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