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A .02 kg bullet moving directly upward at 850 m/s strikes and pass thought a block the mass of 7 kg initially at rest, off-center.
A .02 kg bullet moving directly upward at 850 m/s strikes and pass thought a block the mass of 7 kg initially at rest, off-center. Will the bullet emerge from the other end of the block wit a lower, higher, or equal speed compared to when it passes though the center of mass at 200 m/s? Briefly explain.
let B be the block of length d. let of be the resistive force / length applied by the block on the B bullet as it passes through Block ie f is the fess frictional force applied per unit length of the block as the bullet travels Then , Total force applied by block , F - fod acceleration imparted , as + = m fd m where mus the mass of bullet Now , let U be initial velocity , then using = > V = U + 2 ( 5 0 ) x d = 4 2- 240 - m 2 7 V = ux - 2 71 2 Y - we sign of a is due to m retarding nature of accelration 4 where I the is the final emerging velocity then . In case'I U= 850 mls. VI = J ( 85012- 2fd? lu Puto afd C V1 = 1(8501 - C m case It and VI- 2002 - C NOW ( 8.5 0 1 2 - C 2 0 ( 200 1 2 - C 27 emerging velocity in case I us greater than caseStep by Step Solution
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